Fermat primality test

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The Fermat primality test is a probabilistic test to determine if a number is composite or probably prime.

1 Concept
2 Algorithm and running time
3 Flaws
4 Usage
5 References

Concept

Fermat's little theorem states that if p is prime and <math>1 \le a < p</math>, then

<math>a^{p-1} \equiv 1 \pmod{p}</math>.

If we want to test if n is prime, then we can pick random a's in the interval and see if the equality holds. If the equality does not hold for a value of a, then n is composite. If the equality does hold for many values of a, then we can say that n is probably prime, or a pseudoprime.

It may be in our tests that we do not pick any value for a such that the equality fails. Any a such that

<math>a^{n-1} \equiv 1 \pmod{n}</math>

when n is composite is known as a Fermat liar. If we do pick an a such that

<math>a^{n-1} \not\equiv 1 \pmod{n}</math>

then a is known as a Fermat witness for the compositeness of n.

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Algorithm and running time

The algorithm can be written as follows:

Inputs: n: a value to test for primality; k: a parameter that determines the number of times to test for primality

Output: composite if n is composite, otherwise probably prime

repeat k times:

pick a randomly in the range [1, n − 1]

if a^{n − 1} mod n ≠ 1 then return composite

return probably prime

Using fast algorithms for modular exponentiation, the running time of this algorithm is O(k × log³n), where k is the number of times we test a random a, and n is the value we want to test for primality.

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Flaws

There are certain values of n known as Carmichael numbers for which all values of a for which gcd(a,n)=1 are Fermat liars. Although Carmichael numbers are rare, there are enough of them that Fermat's primality test is often not used in favor of other primality tests such as Miller-Rabin and Solovay-Strassen.

In general, if n is not a Carmichael number then at least half of all

<math>a\in(\mathbb{Z}/n\mathbb{Z})^*</math>

are Fermat witnesses. For proof of this let a be a Fermat witness and a₁, a₂, ..., a_s be Fermat liars. Then

<math>(a\cdot a_i)^{n-1} \equiv a^{n-1}\cdot a_i^{n-1} \equiv a^{n-1} \not\equiv 1\pmod{n}</math>

and so all a × a_i for i = 1, 2, ..., s are Fermat witnesses.

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