Gibbs paradox

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This article is about Gibbs paradox on the extensivity of entropy; for Gibbs mixing paradox, see mixing paradox.

Template:Context In statistical mechanics, a simple derivation of the entropy of an ideal gas, based on the Boltzmann distribution yields an expression for the entropy which is not an extensive variable as it must be, leading to an apparent paradox known as the Gibbs paradox. The difficulty is resolved by requiring the particles be indistinguishable which results in "correct Boltzmann counting". The resulting equation for the entropy of a classical ideal gas is extensive, and is known as the Sackur-Tetrode equation.

If you have a fixed volume of an ideal gas, the measurement of the total entropy within the volume should not change if you were to divide the volume into two (or more) equal partitions, then remove the partitions. However, if you calculate the total entropy by measuring (and adding up) the position and momentum of each individual particle inside the volume (and keep track of each particle separately), then the entropy you calculate will change depending on whether you add and remove partitions inside the fixed volume. This discrepancy is called the Gibb’s Paradox. The paradox is resolved by concluding that every particle is indistinguishable from every other particle in the volume, thus you cannot measure entropy by measuring particles as if each were individually identifiable.

Calculating the Gibbs paradox

If we have an ideal gas of energy U, volume V and with N particles, then we can represent the state of the gas by specifying the 3D momentum vector and the 3D position vector for each of the N particles. This can be thought of as specifying the coordinates of a point in a 6N-dimensional phase space, where each of the axes corresponds to one of the momentum or position coordinates of one of the particles. The set of all possible points that the gas could ever occupy in phase space is specified by the constraint that the gas will have a particular energy:

<math>U=\frac{1}{2m}\sum_{i=1}^{N} \sum_{j=1}^3 p_{ij}^2</math>


and be contained inside of the volume V (let's say V is a box of side X so that X3=V):

<math>0 \le x_{ij} \le X</math>

where [pi1, pi2, pi3] and [xi1, xi2, xi3] are the vector momentum and position of particle i. The first constraint defines the surface of a 3N-dimensional hypersphere of radius (2mU)1/2 and the second is a 3N-dimensional hypercube of volume VN. These combine to form a 6N-dimensional "hypercylinder". Just as the area of the wall of a cylinder is the circumference of the base times the height, so the area φ of the wall of this hypercylinder is:

<math>

\phi(U,V,N) = V^N \left(\frac{2\pi^{\frac{3N}{2}}(2mU)^{\frac{3N-1}{2}}}{\Gamma(3N/2)}\right)~~~~~~~~~~~(1) </math>

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The entropy is proportional to the logarithm of the number of states that the gas could have while satisfying these constraints. Another way of stating Heisenberg's uncertainty principle is to say that we cannot specify a volume in phase space smaller than h3N where h is Planck's constant. The above "area" must really be a shell of thickness h, so we therefore write the entropy as:

<math>\left.\right.

S=k\,\textrm{log}(\phi h/h^{3N}) </math>

where k is the constant of proportionality, Boltzmann's constant. Using Stirling's approximation for the Gamma function, and keeping only terms of order N the entropy becomes:

<math>

S (=?)~~k N \log \left[ V \left(\frac UN \right)^{\frac 32}\right]+ {\frac 32}kN\left( {\frac 53}+ \log\frac{4\pi m}{3h^2}\right) </math>

This quantity is not extensive as can be seen by considering two identical volumes with the same particle number and the same energy. Suppose the two volumes are separated by a barrier in the beginning. Removing or reinserting the wall is reversible, but the entropy difference after removing the barrier is

<math>

\delta S = k \left[ 2N \log(2V) - N\log V - N \log V \right] = 2 k N \log 2 > 0 </math>

which is in contradiction to thermodynamics. This is the Gibbs paradox. It was resolved by J.W. Gibbs himself, by postulating that the gas particles are in fact indistinguishable. This means that all states that differ only by a permutation of particles should be considered as the same point. For example, if we have a 2-particle gas and we specify AB as a state of the gas where the first particle (A) has momentum p1 and the second particle (B) has momentum p2, then this point as well as the BA point where the B particle has momentum p1 and the A particle has momentum p2 should be counted as the same point. It can be seen that for an N-particle gas, there are N! points which are identical in this sense, and so to calculate the volume of phase space occupied by the gas we must divide Equation 1 by N!. This will give for the entropy:

<math>

S = k N \log \left[ \left(\frac VN\right) \left(\frac UN \right)^{\frac 32}\right]+ {\frac 32}kN\left( {\frac 53}+ \log\frac{4\pi m}{3h^2}\right) </math>

which can be easily shown to be extensive. This is the Sackur-Tetrode equation.