Linden, Indiana
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Linden is a town located in Montgomery County, Indiana. As of the 2000 census, the town had a total population of 700.
Geography
Linden is located at 40°11'19" North, 86°54'12" West (40.188695, -86.903311)Template:GR.
According to the United States Census Bureau, the town has a total area of 0.7 km² (0.3 mi²). 0.7 km² (0.3 mi²) of it is land and none of it is covered by water.
Demographics
As of the censusTemplate:GR of 2000, there were 700 people, 302 households, and 202 families residing in the town. The population density was 1,039.5/km² (2,703.8/mi²). There were 321 housing units at an average density of 476.7/km² (1,239.9/mi²). The racial makeup of the town was 98.14% White, 0.29% African American, 0.57% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.00% from other races, and 1.00% from two or more races. 0.43% of the population were Hispanic or Latino of any race.
There were 302 households out of which 34.1% had children under the age of 18 living with them, 54.0% were married couples living together, 7.9% had a female householder with no husband present, and 33.1% were non-families. 27.8% of all households were made up of individuals and 11.9% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.80.
In the town the population was spread out with 25.6% under the age of 18, 6.6% from 18 to 24, 31.0% from 25 to 44, 23.0% from 45 to 64, and 13.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 97.7 males. For every 100 females age 18 and over, there were 91.5 males.
The median income for a household in the town was $36,750, and the median income for a family was $41,696. Males had a median income of $32,955 versus $22,679 for females. The per capita income for the town was $16,733. 5.0% of the population and 3.9% of families were below the poverty line. 6.0% of those under the age of 18 and 8.4% of those 65 and older were living below the poverty line.