Ratio test
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In mathematics, the ratio test is a test (or "criterion") for the convergence of a series whose terms are real or complex numbers. The test was first published by Jean le Rond d'Alembert and is sometimes known as d'Alembert's ratio test. The ratio test is defined as:
- <math>L = \lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|</math>
where
- lim denotes the limit as n goes to infinity,
- an and an+1 are the nth and (n+1)th terms of an infinite series and
- L is a label for the result of the ratio test.
The results of the ratio test show that:
- if <math> L<1 \!</math> the series converges absolutely, or
- if <math> L>1 \!</math> the series diverges, or
- if <math> L=1 \!</math> the test is inconclusive (there exists both convergent and divergent series that satisfy this case).
For example, any series in the form:
- <math>\sum_{n=1}^\infty f_n</math>
can be applied to the ratio test.
Contents |
Examples
Converging
Consider the series:
- <math>\sum_{n=1}^\infty\frac{n}{e^n}</math>
Putting this into the ratio test:
\frac{a_{n+1}}{a_n}\right|</math> \frac{\frac{n+1}{e^{n+1}}}{\frac{n}{e^n}}\right|</math> \frac{n+1}{e^{n+1}}\cdot\frac{e^n}{n}\right|</math> \frac{n+1}{n}\cdot\frac{e^n}{e^n\cdot e}\right|</math> (1+\frac{1}{n})\cdot\frac{1}{e}\right|</math> =<math>1\cdot\frac{1}{e}</math> =<math>\frac{1}{e} (<1)</math>
Thus the series converges as <math>\frac{1}{e}</math> is less than 1.
Diverging
Consider the series:
- <math>\sum_{n=1}^\infty\frac{e^n}{n}</math>
Putting this into the ratio test:
\frac{a_{n+1}}{a_n}\right|</math> \frac{\frac{e^{n+1}}{n+1}}{\frac{e^n}{n}}\right|</math> \frac{e^{n+1}}{n+1}\cdot\frac{n}{e^n}\right|</math> \frac{n}{n+1}\cdot\frac{e^n\cdot e}{e^n}\right|</math> (1-\frac{1}{n+1})\cdot e\right|</math> =<math>1\cdot e</math> =<math>\!\, e (>1)</math>
Thus the series diverges as <math>e</math> is greater than 1.
Inconclusive
If one has
- <math>\lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|=1</math>
it is impossible to deduce from the ratio test if the series converges or diverges.
For example, the series
- <math>\sum_{n=1}^\infty 1</math>
diverges, but
- <math>\lim_{n\rightarrow\infty}\left|\frac{1}{1}\right| = 1.</math>
On the other hand,
- <math>\sum_{n=1}^\infty \frac{1}{n^2} </math>
converges absolutely, but
- <math>\lim_{n\rightarrow\infty}\left|\frac{\frac{1}{(n+1)^2}}{\frac{1}{n^2}}\right| = 1.</math>
Finally,
- <math>\sum_{n=1}^\infty (-1)^n\frac{1}{n} </math>
converges conditionally but
- <math>\lim_{n\rightarrow\infty}\left|\frac{\frac{(-1)^{n+1}}{(n+1)}}{\frac{(-1)^{n}}{n}}\right| = 1.</math>
L=1 and Raabe's test
As seen in the previous example, the ratio test is inconclusive when the limit of the ratio is 1. An extension of the ratio test due to Raabe sometimes allows one to deal with this case. Raabe's test states that if
- <math>\lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|=1</math>
and if a positive number c exists such that
- <math>\lim_{n\rightarrow\infty}
\,n\left(\,\left|\frac{a_{n+1}}{a_n}\right|-1\right)=-1-c</math>
then the series will be absolutely convergent. d'Alembert's ratio test and Raabe's test are the first and second theorem in a hierarchy of such theorems due to Augustus De Morgan.
See also
References
- Knopp, Konrad, "Infinite Sequences and Series", Dover publications, Inc., New York, 1956. (§ 3.3, 5.4) ISBN 0486601536
- Whittaker, E. T., and Watson, G. N., A Course in Modern Analysis, fourth edition, Cambridge University Press, 1963. (§ 2.36, 2.37) ISBN 0521588073de:Quotientenkriterium
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