Springfield, Marquette County, Wisconsin
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Springfield is a town located in Marquette County, Wisconsin. As of the 2000 census, the town had a total population of 628.
Geography
Image:WIMap-doton-Springfield c.pngAccording to the United States Census Bureau, the town has a total area of 90.5 km² (34.9 mi²). 89.6 km² (34.6 mi²) of it is land and 0.9 km² (0.3 mi²) of it is water. The total area is 0.97% water.
Demographics
As of the census2 of 2000, there were 628 people, 273 households, and 188 families residing in the town. The population density was 7.0/km² (18.1/mi²). There were 542 housing units at an average density of 6.0/km² (15.7/mi²). The racial makeup of the town was 97.29% White, 0.00% African American, 1.75% Native American, 0.00% Asian, 0.00% Pacific Islander, 0.48% from other races, and 0.48% from two or more races. 1.27% of the population were Hispanic or Latino of any race.
There were 273 households out of which 25.3% had children under the age of 18 living with them, 63.0% were married couples living together, 2.9% had a female householder with no husband present, and 31.1% were non-families. 27.8% of all households were made up of individuals and 12.8% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.82.
In the town the population was spread out with 19.9% under the age of 18, 5.6% from 18 to 24, 23.4% from 25 to 44, 33.4% from 45 to 64, and 17.7% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 107.9 males. For every 100 females age 18 and over, there were 107.0 males.
The median income for a household in the town was $35,109, and the median income for a family was $41,875. Males had a median income of $30,750 versus $21,250 for females. The per capita income for the town was $17,593. 10.3% of the population and 6.2% of families were below the poverty line. 8.8% of those under the age of 18 and 14.3% of those 65 and older were living below the poverty line.